How do you find the definite integral of int 1/(x+2) from [-1,1]?

1 Answer
Mia
Dec 4, 2016

ln3

Explanation:

Let u=x+2
" "
then " "du=dx
" "
int1/(x+2) dx
" "
=int (du)/u
" "
=lnu + C
" "
=lnabs(x+2) + C
" "
" "
int_-1^1 1/(x+2) dx
" "
=lnabs(1+2) - lnabs(-1+2)
" "
=lnabs3-lnabs1
" "
=ln3-ln1
" "
=ln3-0
" "
=ln3

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