How do you find the definite integral of $int (3x-x^2)dx$ from $[1,3]$ ?

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Answer 1 · 2015-10-31T12:55:00

$10/3$

Use laws of integration to write the anti-derivative, and then use the Fundamental Theorem of Calculus to evaluate it between the limits given.

$int_1^3(3x-x^2)dx=[3x^2/2-x^3/3]_1^3$

$=(27/2-27/3)-(3/2-1/3)$

$=10/3$

How do you find the definite integral of int (3x-x^2)dxint (3x-x^2)dx from [1,3][1,3]?