How do you find the derivative $h (x) = x^{2} arctan x$ $h(x)=x^2arctanx$ ?

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Answer 1 · 2018-01-20T04:40:11

$h'(x) = x^2/(x^2+1)+2xarctan(x)$

$h(x) = x^2arctan(x)$

$h'(x) = x^2 * d/dx arctan(x) + d/dx x^2 * arctan(x)$

Apply standard differential and power rule.

$h'(x) = x^2 * 1/(x^2+1) + 2x * arctan(x)$

$= x^2/(x^2+1)+2xarctan(x)$

How do you find the derivative h(x)=x^2arctanxh(x)=x2arctanxh(x)=x^2arctanx?