How do you find the derivative of $(29arctanx)^(1/2)$ ?

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Answer 1 · 2015-04-21T17:01:22

Let y= $(29arctanx)^(1/2)$

$y^2= 29 arctanx$ . Now differentiate w.r.t x

$2ydy/dx= 29/(1+x^2)$

$dy/dx= 29/{2(1+x^2)} 1/(29arctanx)^(1/2)$

= $sqrt29/[2(1+x^2) (arctanx)^(1/2)]$

How do you find the derivative of (29arctanx)^(1/2)(29arctanx)^(1/2)?