How do you find the derivative of $5^tanx$ ?

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Answer 1 · 2016-11-30T18:42:28

$d/dx(5^(tan x))=(5^tan x)*ln 5*sec^2 x$

The formula to differentiate is

$d/dx(a^u)=a^u*ln a*d/dx(u)$

therefore

$d/dx(5^tan x)=5^tanx*ln 5*d/dx(tan x)$

$d/dx(5^tan x)=5^tanx*ln 5*sec^2 x*(dx/dx)$

$d/dx(5^(tan x))=(5^tan x)*ln 5*sec^2 x$

God bless....I hope the explanation is useful.

How do you find the derivative of 5^tanx5^tanx?