Question

How do you find the derivative of `8^(2x)`?

Answer 1

`d/dx8^(2x)=8^(2x)*2ln8`

Explanation:

Applying the rule `d/dxa^(u(x))=a^u*lna*(du)/dx`, to this question we get

`d/dx8^(2x)=8^(2x)*ln8*2`