How do you find the derivative of arcsin(sinx)? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer Leland Adriano Alejandro Jan 17, 2016 ddx(arcsin(sinx))=1 Explanation: ddx(arcsin(sinx))=1√1−sin2x⋅cosx=cosxcosx=1 Answer link Related questions What is the derivative of f(x)=sin−1(x) ? What is the derivative of f(x)=cos−1(x) ? What is the derivative of f(x)=tan−1(x) ? What is the derivative of f(x)=sec−1(x) ? What is the derivative of f(x)=csc−1(x) ? What is the derivative of f(x)=cot−1(x) ? What is the derivative of f(x)=cos−1(x)x ? What is the derivative of f(x)=tan−1(ex) ? What is the derivative of f(x)=cos−1(x3) ? What is the derivative of f(x)=ln(sin−1(x)) ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 6079 views around the world You can reuse this answer Creative Commons License