Question

How do you find the derivative of `arcsin(x/3)`?

Answer 1

See below

Explanation:

Let `y=arcsin(x/3)`

`siny=x/3`

`cosydy/dx=1/3`

`dy/dx=1/(3cosy)=1/(3sqrt(1-(x/3)^2))`

The general rule is for `f:x|->b arcsinx`, `f'(x)=1/sqrt(1-x^2)b`