How do you find the derivative of: $arcsin x + arccos x$ ?

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Answer 1 · 2015-05-14T10:23:30

Since the derivative of

$y=arcsinx$

is

$y'=1/sqrt(1-x^2)$

and the derivative of

$y=arccosx$

is

$y'=-1/sqrt(1-x^2)$ ,

The derivative of the function is $0$ .

How do you find the derivative of: arcsin x + arccos xarcsin x + arccos x?