How do you find the derivative of exponential function $y = e^9 ln x$ ?

Question

1711 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-16T14:20:29

The product rule states that, for a function $y=f(x)g(x)$ ,

$(dy)/(dx)=f'(x)g(x)+f(x)g'(x)$

So, derivating your function:

$(dy)/(dx)=e^9ln(x)+e^9*(1/x)$

Thus,

$(dy)/(dx)=e^9(ln(x)+(1/x))$

How do you find the derivative of exponential function y = e^9 ln xy = e^9 ln x?