How do you find the derivative of $f(x)=sin(arccos t)$ ?

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Answer 1 · 2017-01-01T18:37:30

$-t/sqrt(1-t^2)$

As we know $sin(arccos(t))=sqrt(1-t^2)$ so

$d/(dt)sqrt(1-t^2) = -t/sqrt(1-t^2)$

How do you find the derivative of f(x)=sin(arccos t)f(x)=sin(arccos t)?