How do you find the derivative of $ln(10/x)$ ?

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Answer 1 · 2016-10-18T15:07:02

$d/dxln(10/x) = -1/x$

Simply the expression using the rule of logs and use $d/dx(lnx)=1/x$

So, $d/dxln(10/x) = d/dx{ln10-lnx}$

$= d/dxln10-d/dxlnx$
$= 0-1/x$
$= -1/x$

How do you find the derivative of ln(10/x)ln(10/x)?