Question

How do you find the derivative of `ln^2 x`?

Answer 1

I found:
`y'=(2ln(x))/x`

Explanation:

I would use the Chain Rule to deal first with the derivation of `()^2` and then multiply times the derivative of the log:
`y'=2[ln(x)]^(2-1)*1/x=(2ln(x))/x`