How do you find the derivative of $ln (x^{12})$ $ln(x^12)$ ?

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Answer 1 · 2016-10-18T09:15:37

The answer is $\frac{12}{x}$ $12/x$

It's the derivative of the type $ln (u (x))$ $ln(u(x))$
The derivative is $(u '(x))/(u(x))$
So the answer is $(12x^11)/x^12=12/x^11$

How do you find the derivative of ln(x^12)ln(x12)ln(x^12)?