How do you find the derivative of $lnx^(1/2)$ ?

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Answer 1 · 2016-09-08T15:19:28

$d/dxlnx^(1/2)=1/(2x)$

We can

either use the chain rule here

$d/dxlnx^(1/2)=d/dx^(1/2)(lnx^(1/2))xxd/dx x^(1/2)$

= $1/x^(1/2)xx1/2xx x^(-1/2)$

= $1/x^(1/2)xx1/2xx1/x^(1/2)=1/(2x)$

or as $lnx^(1/2)=1/2lnx$

$d/dxlnx^(1/2)=1/(2x)$

How do you find the derivative of lnx^(1/2)lnx^(1/2)?