Question

How do you find the derivative of `log(8x-1)`?

Answer 1

`8/(8x - 1 )`

Explanation:

using the`color(blue)(" chain rule ")`

`d/dx(f(g(x)) = f'(g(x) . g'(x)`

and knowing that #d/dx(logx) = 1/x

`d/dx(log(8x-1)) = 1/(8x-1) d/dx (8x-1) = 8/(8x-1)`