How do you find the derivative of $sin^2x^2$ ?

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Answer 1 · 2016-01-10T16:10:53

$4xsinx^2cosx^2$

before starting note that $sin^2(x) = (sinx)^2$

this form makes it'easier' to apply the chain rule.

rewriting $sin^2x^2 = (sinx^2)^2$

differentiating using the chain rule gives:

$2(sinx^2).d/dx(sinx^2) = 2(sinx^2)(cosx^2).d/dx(x^2)$

$= 2(sinx^2)cosx^2(2x)$

$rArr d/dx(sin^2x^2 ) = 4xsinx^2cosx^2$

How do you find the derivative of sin^2x^2sin^2x^2?