Question

How do you find the derivative of `sqrt(1-x^2)`?

Answer 1

`(d y)/(d x)=-x/(sqrt(1-x^2))`

Explanation:

`y=sqrt(1-x^2)`

`"let us remember that : "y=sqrt u" ; "y^'=u^'/(2sqrt u)`

`(d y)/(d x)=-(cancel(2)x)/(cancel(2) sqrt(1-x^2))`

`(d y)/(d x)=-x/(sqrt(1-x^2))`