How do you find the derivative of $\sqrt{3 x}$ $sqrt(3x)$ ?

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How do you find the derivative of $\sqrt{3 x}$ $sqrt(3x)$ ?

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Answer 1 · 2015-12-29T16:17:12

The answer is:
$\frac{d}{d x} \sqrt 3 x = \frac{\sqrt 3}{2 \sqrt x}$ $d/dx √3x=(√3)/(2√x)$

Explanation:

$\frac{d}{d x} (\sqrt x) (\sqrt 3) = (\sqrt 3) \frac{d}{d x} \sqrt x$ $d/dx (√x)( √3)=(√3 )d/dx √x$
and
$\frac{d}{d x} (\sqrt x) = \frac{1}{2 \sqrt x}$ $d/dx (√x)=1/(2√x)$

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How do you find the derivative of $\sqrt{3 x}$ $sqrt(3x)$ ?

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