How do you find the derivative of the function: $arccos (e^{2 x})$ $arccos (e^(2x))$ ?

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Answer 1 · 2015-04-29T08:44:32

The derivative of $y = arccos f (x)$ $y=arccosf(x)$ is

$y'=-1/sqrt(1-[f(x)]^2)*f'(x)$ ,

so:

$y'=-1/sqrt(1-e^(4x))*2e^(2x)$ .

How do you find the derivative of the function: arccos (e^(2x))arccos(e2x)arccos (e^(2x))?