How do you find the derivative of $(x^2-1)^3$ ?

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Answer 1 · 2015-07-06T03:19:30

I found: $6x(x^2-1)^2$

I would use the Chain Rule to derive $()^3$ first and then multiply times the derivative of the argument and get:
$y'=3(x^2-1)^2*2x=6x(x^2-1)^2$

How do you find the derivative of (x^2-1)^3(x^2-1)^3?