How do you find the derivative of (x^2+x)^2? Calculus Basic Differentiation Rules Chain Rule 1 Answer Sonnhard ยท Jacobi J. May 25, 2018 f'(x)=2(2x^3+3x^2+x) Explanation: Using that (x^n)'=nx^(n-1) (Power Rule) and the Chain rule , then we get f'(x)=2(x^2+x)(2x+1) Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of y= 6cos(x^2) ? How do you find the derivative of y=6 cos(x^3+3) ? How do you find the derivative of y=e^(x^2) ? How do you find the derivative of y=ln(sin(x)) ? How do you find the derivative of y=ln(e^x+3) ? How do you find the derivative of y=tan(5x) ? How do you find the derivative of y= (4x-x^2)^10 ? How do you find the derivative of y= (x^2+3x+5)^(1/4) ? How do you find the derivative of y= ((1+x)/(1-x))^3 ? See all questions in Chain Rule Impact of this question 1940 views around the world You can reuse this answer Creative Commons License