Question

How do you find the derivative of `y=1+x-cosx`?

Answer 1

`dy/dx=1+sinx`

Explanation:

differentiate using `color(blue)"standard derivatives"`

`color(orange)"Reminder"`

`D(" constant" )=0color(white)(xxxx)D(x)=1`

`"and " D(cosx)=-sinx`

`y=1+x-cosxrArrdy/dx=0+1-(-sinx)`

`=1+sinx`