How do you find the derivative of y = arccos(e^(5x))? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer A. S. Adikesavan Apr 10, 2016 (-5e^(5x))/sqrt(1-e^10x), x<=0. Explanation: cos y=e^(5x). (-sin y) y'=5e^(5x). y'=-(5e^(5x))/(1-cos^2y =.-(5e^(5x))/(1-e^(10x) Note that if x>0, e^(5x)>1, cos y > 1 and y becomes unreal. Answer link Related questions What is the derivative of f(x)=sin^-1(x) ? What is the derivative of f(x)=cos^-1(x) ? What is the derivative of f(x)=tan^-1(x) ? What is the derivative of f(x)=sec^-1(x) ? What is the derivative of f(x)=csc^-1(x) ? What is the derivative of f(x)=cot^-1(x) ? What is the derivative of f(x)=(cos^-1(x))/x ? What is the derivative of f(x)=tan^-1(e^x) ? What is the derivative of f(x)=cos^-1(x^3) ? What is the derivative of f(x)=ln(sin^-1(x)) ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 2531 views around the world You can reuse this answer Creative Commons License