How do you find the derivative of $y = arcsin (3 x + 4)$ $y = arcsin(3x + 4)$ ?

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Answer 1 · 2016-04-08T16:53:06

$y'=3/sqrt(-9x^2-24x-15)$

$y'=1/sqrt(1-(3x+4)^2) *3$ -> chain rule

$y'=3/(sqrt(1-(9x^2+24x+16))$ ->FOIL

$y'=3/sqrt(1-9x^2-24x-16)$ ->Distribute the negative 1

$y'=3/sqrt(-9x^2-24x-15)$ ->Combine like terms

How do you find the derivative of y = arcsin(3x + 4)y=arcsin(3x+4)y = arcsin(3x + 4)?