How do you find the derivative of $y = arcsin(x^5)$ ?

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Answer 1 · 2016-06-23T11:07:21

$y' = (5x^4)/(sqrt{1 - x^{10})$

$y = arcsin(x^5)$

$sin y = x^5$

$cos y \ y' = 5x^4$

$y' = (5x^4)/(cos y)$

$y' = (5x^4)/(sqrt{1 - sin^2 y})$

$y' = (5x^4)/(sqrt{1 - (x^5)^2})$

$y' = (5x^4)/(sqrt{1 - x^{10})$

How do you find the derivative of y = arcsin(x^5) y = arcsin(x^5) ?