How do you find the derivative of $y = {arcsin e}^{x}$ $y=arcsine^x$ ?

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Answer 1 · 2016-01-18T13:14:38

$\frac{d y}{d x} = \frac{e^{x}}{\sqrt{1 - e^{2 x}}}$ $dy/dx=e^x/sqrt(1-e^(2x)$

From standard rules of differentiation we get

$\frac{d y}{d x} {sin}^{- 1} (e^{x}) = \frac{1}{\sqrt{1 - {(e^{x})}^{2}}} \cdot e^{x}$ $dy/dx sin^(-1)(e^x)=1/sqrt(1-(e^x)^2)*e^x$

How do you find the derivative of y=arcsine^xy=arcsinexy=arcsine^x?