How do you find the derivative of $y=cos(cosx)$ ?

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Answer 1 · 2018-04-05T16:55:49

$dy/dx=sinx*sin(cosx)$

First from the differentiation of trigonometric functions :

$d/dx cosx=-sinxdx$

$d/dxcosu=-sinu*du$

Where $u$ is a function of $x$

so when You differentiate $y=cos(cosx)$

You get the following:

$dy= -sin(cosx)dcosx$

which gives You:

$dy=(-sin(cosx))*(-sinx*dx)$

and by simpilification you get:

$dy/dxcosx=sinx*sin(cosx)$

How do you find the derivative of y=cos(cosx)y=cos(cosx) ?