Question

How do you find the derivative of `y = [e^(-1) + e^(t)]^3`?

Answer 1

The answer is : `3(e^(-1) + e^t)^2*e^t`

`dot y = dot [(e^(-1) + e^t)^3] = 3(e^(-1) + e^t)^2*dot ((e^(-1)+e^t))`

`= 3(e^(-1) + e^t)^2*e^t`