How do you find the derivative of y=e^(2x^3)? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer Henry W. Oct 12, 2016 (dy)/(dx)=6x^2e^(2x^3) Explanation: Use the chain rule: (dy)/(dx)=(dy)/(du)*(du)/(dx) y=e^(2x^3), let u=2x^3 (dy)/(du)=e^u=e^(2x^3), (du)/(dx)=6x^2 So (dy)/(dx)=e^(2x^3)*6x^2=6x^2e^(2x^3) Answer link Related questions What is the derivative of f(x)=ln(g(x)) ? What is the derivative of f(x)=ln(x^2+x) ? What is the derivative of f(x)=ln(e^x+3) ? What is the derivative of f(x)=x*ln(x) ? What is the derivative of f(x)=e^(4x)*ln(1-x) ? What is the derivative of f(x)=ln(x)/x ? What is the derivative of f(x)=ln(cos(x)) ? What is the derivative of f(x)=ln(tan(x)) ? What is the derivative of f(x)=sqrt(1+ln(x) ? What is the derivative of f(x)=(ln(x))^2 ? See all questions in Differentiating Logarithmic Functions with Base e Impact of this question 11417 views around the world You can reuse this answer Creative Commons License