Question

How do you find the derivative of `y=lnx^3`?

Answer 1

I got `y'=3/x`

Explanation:

We can use one of the properties of logs that allow us to write it as:
`y=3ln(x)`
We can then derive as usual:
`y'=3*1/x`

We can also use the Chain Rule deriving the log first as it is and multiply by the derivative of the argument:
`y'=1/x^3*3x^2=` simplify:
`=3/x`
...again