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How do you find the derivative using limits of $f(x)=3$ ?

1 Answer

Dec 15, 2016

$f'(x) = 0$

Explanation:

The definition of the derivative of $y=f(x)$ is

$f'(x)=lim_(h rarr 0) ( f(x+h)-f(x) ) / h$

So with $f(x) = 3$ then the derivative of $y=f(x)$ is given by:

$\ \ \ \ \ f'(x) = lim_(h rarr 0) ( (3) - (3) ) / h$
$" " = lim_(h rarr 0) 0$
$:. f'(x) = 0$

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