How do you find the derivative $y = \sqrt{{tan}^{- 1} x}$ $y=sqrt(tan^-1 x)$ ?

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Answer 1 · 2015-04-17T13:30:22

#1. Firstly find the derivative of arctanx...

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#2. Lastly, use implicit differentiation to find the derivative of y=(arctanx)^(1/2)

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How do you find the derivative y=sqrt(tan^-1 x)y=√tan−1xy=sqrt(tan^-1 x)?