How do you find the derivatives of $y=log_x(a)$ ?

Question

13023 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-16T11:41:04

$d/(dx) (log_x(a)) = -lna/(xln^2(x))$

You can use this property of logarithms:

$log_b(a) = lna/lnb$

so that:

$y= lna/lnx$

and:

$(dy)/(dx) = d/(dx) (log_x(a))= d/(dx) (lna/lnx) = lna*1/x*(-1/ln^2(x))= -lna/(xln^2(x))$

How do you find the derivatives of y=log_x(a)y=log_x(a)?