How do you find the differential $d y$ $dy$ of the function $y = x sin x$ $y=xsinx$ ?

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Answer 1 · 2017-02-24T19:43:51

$d y = (sin x + x cos x) d x$ $dy=(sinx+xcosx)dx$

First, we need to differentiate this function using the product rule:

$\frac{d y}{d x} = sin x + x cos x$ $dy/dx=sinx+xcosx$

Now we can multiply the derivative by $d x$ $dx$ to get $d y$ $dy$ on its own:

$d y = (sin x + x cos x) d x$ $dy=(sinx+xcosx)dx$

How do you find the differential dydydy of the function y=xsinxy=xsinxy=xsinx?