How do you find the discriminant of $4 x^{2} + 12 x + 9 = 0$ $4x^2 +12x+9=0$ ?

Question

12574 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-13T08:31:58

See explanation.

For a quadratic equation $a x^{2} + b x + c = 0$ $ax^2+bx+c=0$ the discriminant is defined as:

$Delta=b^2-4ac$

In the given equation we have:

$a=4$ , $b=12$ and $c=9$ , so:

$Delta=12^2-4*4*9=144-144=0$