How do you find the exact value of the third side given $triangle PQR$ , $p=126, q=214, mangleR=42$ ?

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Answer 1 · 2017-03-12T19:49:12

$r~=146,95$

You would apply the cosine theorem:

$r=sqrt(p^2+q^2-2pqcos hatR)$

$=sqrt(126^2+214^2-2*126*214*cos42°)~=146,95$

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How do you find the exact value of the third side given triangle PQRtriangle PQR, p=126, q=214, mangleR=42p=126, q=214, mangleR=42?