How do you find the general solutions for $sin^2x=3cos^2x$ ?

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Answer 1 · 2015-10-07T04:17:16

Solve $sin^2 x = 3cos^2 x$

Ans: $pi/3 and (2pi)/3$

$sin^2 x = 3cos^2 x$
$tan^2x = 3$
t $an x = +- sqrt3$
a. $tan x = sqrt3$ --> $x = pi/3 + kpi$
b. $tan x = -sqrt3$ --> $x = (2pi)/3 + kpi$

How do you find the general solutions for sin^2x=3cos^2xsin^2x=3cos^2x?