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How do you find the general solutions for $\sqrt{3} - 2 sin (6 x) = 0$ $sqrt(3) - 2Sin(6x) = 0$ ?

1 Answer

Aug 22, 2015

$x = 10^{o} \pm n \cdot 60^{o} XXXX or XXXX x = 20^{o} \pm n \cdot 60^{o}$ $x = 10^o +-n*60^ocolor(white)("XXXX")orcolor(white)("XXXX")x=20^o +-n*60^o$
$color(white)("XXXXXXXX")"for "AA n in ZZ$

Explanation:

$sqrt(3)-2sin(6x) = 0$
$rArrcolor(white)("XXXX")sin(6x) = sqrt(3)/2$

$rArr 6x = 60^o +- n*360^ocolor(white)("XXX")orcolor(white)("XXX")6x = 120^o +-n*360$

$rArr x = 10^o +- n*60^o color(white)("XXXX")orcolor(white)("XXX")x=20^o +-n*60^o$

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