How do you find the general solutions for $tan x + 1 = 0$ $tanx+1=0$ ?

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How do you find the general solutions for $tan x + 1 = 0$ $tanx+1=0$ ?

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Answer 1 · 2015-09-23T03:19:48

Refer to explanation

Explanation:

It is $tan x + 1 = 0 \Rightarrow tan x = - 1 \Rightarrow tan x = tan (- \frac{π}{4}) \Rightarrow x = k \cdot π - \frac{π}{4}$ $tanx+1=0=>tanx=-1=>tanx=tan(-pi/4)=> x=k*pi-pi/4$

The general solutions are $x = k \cdot π - \frac{π}{4}$ $x=k*pi-pi/4$ where k belongs to integers

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How do you find the general solutions for $tan x + 1 = 0$ $tanx+1=0$ ?

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How do you find the general solutions for tanx+1=0tanx+1=0tanx+1=0?

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How do you find the general solutions for $tan x + 1 = 0$ $tanx+1=0$ ?