How do you find the general solutions for tanx = 2sinx?

1 Answer
Aug 13, 2015

tanx = 2sinx

tanx - 2sinx =0

sinx/cosx - 2sinx =0

sinx(1/cosx -2) =0

sinx =0" " or " "1/cosx-2=0

sinx =0" " or " "cosx=1/2

sinx = 0 hArr x=pin for n an Integer.

cosx=1/2 hArr x = pi/3 +2pin " or " x = -pi/3 +2pin

The solutions are:

{: (x = pi n), (x = pi/3 +2pi n), (x = - pi/3 +2pi n):} } for n an Integer.