How do you find the indefinite integral of int 1/(2x+5) dx?

1 Answer
Oct 16, 2015

int1/(2x+5)dx=1/2ln|2x+5|+C

Explanation:

If we use substitution and let u=2x+5, then the differential du=2dx and so 1/2du=dx

We may then write this original integral in terms of u as follows :

1/2int1/u du

This may be evaluated by rules of integration as 1/2ln|u|+C.

Now substituting back to x we get the final answer as 1/2ln|2x+5|+C