How do you find the indefinite integral of $int (1 / csc x) dx$ ?

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Answer 1 · 2015-09-25T01:04:33

Refer to explanation

Well we have that

$cscx=1/sinx$ hence

$int(1/cscx)dx=int(1/(1/sinx))dx=int sinxdx=-cosx+c$

How do you find the indefinite integral of int (1 / csc x) dxint (1 / csc x) dx?