How do you find the indefinite integral of $int 1/(x+1)$ ?

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Answer 1 · 2017-08-04T06:04:44

The answer is $=ln|1+x| + C$

We need

$int(dx)/x=ln|x|+C$

Therefore,

$int(dx)/(1+x)=ln|1+x| + C$

How do you find the indefinite integral of int 1/(x+1)int 1/(x+1)?