How do you find the indefinite integral of $int 1/(x-5)$ ?

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Answer 1 · 2016-12-16T10:41:42

$int1/(x-5)dx=ln|(x-5)|+C$

$int(f'(x))/(f(x))dx=ln|f(x)|+C$

$int1/(x-5)dx$

$x!=5$

$d/(dx)(x-5)=1$

$int1/(x-5)dx=ln|(x-5)|+C$

How do you find the indefinite integral of int 1/(x-5)int 1/(x-5)?