Question

How do you find the indefinite integral of `int (x^2-3x+2)/(x-1) dx`?

Answer 1

The function is `y = 1/2x^2 - 2x + C`.

Explanation:

I would recommend factoring the numerator and the denominator to see if we can eliminate/simplify before integrating.

`=>int((x - 2)(x - 1))/(x - 1)`

`=>int(x - 2)`

`=> 1/2x^2 - 2x+ C`

You can always verify your answer by differentiating. You will see the integration worked.

Hopefully this helps!