How do you find the indefinite integral of $int (x^2-3x+2)/(x-1) dx$ ?

Question

7264 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-31T22:24:22

The function is $y = 1/2x^2 - 2x + C$ .

I would recommend factoring the numerator and the denominator to see if we can eliminate/simplify before integrating.

$=>int((x - 2)(x - 1))/(x - 1)$

$=>int(x - 2)$

$=> 1/2x^2 - 2x+ C$

You can always verify your answer by differentiating. You will see the integration worked.

Hopefully this helps!

How do you find the indefinite integral of int (x^2-3x+2)/(x-1) dxint (x^2-3x+2)/(x-1) dx?