How do you find the indefinite integral of x2x3+3dx?

1 Answer
Dec 7, 2016

The answer is =29(x3+3)32+C

Explanation:

We use xndx=xn+1n+1+C(n1)

Lets' do this by substitution

Let u=x3+3

du=3x2dx, , x2dx=du3

Therefore,

x2x3+3dx

=13udu

=13u12du

=13u3232

=29u32

=29(x3+3)32+C