Question

How do you find the intercept and vertex of `x^2+6y=0`?

Answer 1

Vertex is at`(0,0)` and Intercept is at origin`(0,0)`

Explanation:

`6*y= - x^2 or y= -1/6*x^2` or `y=-1/6*(x-0)^2+0`: Vertex is at `0,0`
putting x=0; we get y=0 So the intercept is at origin(0,0) graph{-1/6x^2 [-10, 10, -5, 5]}[Ans]