How do you find the intercept and vertex of y = x^2 - 4x - 2y=x24x2?

1 Answer
Jul 24, 2018

"vertex "=(2,-6)," intercepts "=2+-sqrt6vertex =(2,6), intercepts =2±6

Explanation:

"The equation of a parabola in "color(blue)"vertex form"The equation of a parabola in vertex form is.

•color(white)(x)y=a(x-h)^2+kxy=a(xh)2+k

"where "(h,k)" are the coordinates of the vertex and a"where (h,k) are the coordinates of the vertex and a
"is a multiplier"is a multiplier

"to obtain this form "color(blue)"complete the square"to obtain this form complete the square

y=x^2+2(-2)x+4-4-2y=x2+2(2)x+442

y=(x-2)^2-6larrcolor(red)"in vertex form"y=(x2)26in vertex form

color(magenta)"vertex "=(2,-6)vertex =(2,6)

"to obtain the x-intercepts let y = 0"to obtain the x-intercepts let y = 0

(x-2)^2-6=0(x2)26=0

(x-2)^2=6(x2)2=6

color(blue)"take the square root of both sides"take the square root of both sides

x-2=+-sqrt6larrcolor(blue)"note plus or minus"x2=±6note plus or minus

"add 2 to both sides"add 2 to both sides

x=2+-sqrt6larrcolor(red)"exact values"x=2±6exact values