How do you find the intercepts of x2yx2+4y=0?

2 Answers
Mar 24, 2015

For the intercepts you set alternately x=0 and y=0 in your function:
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and graphically:
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Mar 24, 2015

On the X-axis y=0
So
x2yx2+4y=0
becomes
x2(0)x2+4(0)=0
x2=0
x=0

On the Y-axis x=0
and the original equation
x2yx2+4y=0
becomes
(0)2y(0)2+4y=0
y=0

The only intercept for the given equation occurs at (0,0)